Answer: 3e-1
Step-by-step explanation: when it's going behind the decimal it will always be negative plus the reason it's one is because if you slide the decimal once it'll be the complete opposite
Answer: The question is incomplete
Step-by-step explanation: The answer to this question cannot be determined correctly since an important detail is missing.
However, let me explain how you would normally go about it by using an example of mine. If for example the ratio of yes votes to no votes was 8 to 5, and the question requires you to calculate how many yes votes were there as indicated in your question, then the first step would be to find the total number of both sides of the ratio. That is add 8 to 5 which gives you 13. This means if there was a total of 13 votes cast, every yes vote stands for 8 out of 13 votes and every no vote stands for 5 out of 13 votes.
To express it mathematically, every yes vote would be 8/13 of the total (12779) and every no vote would be 5/13 of the total (12779).
Therefore to determine how many yes votes there was, is calculated as follows;
Let yes votes be y and no votes be x'
y = (8/13) * 12779
y = 102232/13
y = 7864
<em>Based on my example that the ratio of yes votes to no votes is 8 to 5, </em>
Then the number of yes votes was 7,864.
Answer:
d. 0.0948 ± 4.032(0.0279)
Step-by-step explanation:
A 99% confidence interval for the coefficient of promotional expenditures is, First, compute the t critical value then find confidence interval.
The t critical value for the 99% confidence interval is,
The sample size is small and two-tailed test. Look in the column headed es = 0.01 and the row headed in the t distribution table by using degree of freedom is here
for (n-2=5) degree of freedom and 99% confidence ; critical t =4.032
therefore 99% confidence interval for the slope =estimated slope -/+ t*Std error
= 0.094781123 -/+ 4.032* 0.027926367 = -0.017822 to 0.207384
Answer:
Add all and you will get the answer...........
D. The solution is 35, which represents the number of miles she runs each week.