(A)






(B)




But we assume
is a function of
alone, so there is not potential function here.
(C)






For (A) and (C), we have
, which makes
for both.
Answer:
Step-by-step explanation:
For the first problem, we can plug in the slope of
for
:

To solve for
, we plug in the given point
:



This gives us the equation:

For the second problem, we can plug in the slope of
for
:

To solve for
, we plug in the given point
:


This gives us the equation:

I think it would be a one i eight chance of that happening 1/8
Answer:
x = 1
Step-by-step explanation:
4(2x + 1) - 3 = - 3(x - 4) ← distribute parenthesis on both sides
8x + 4 - 3 = - 3x + 12
8x + 1 = - 3x + 12 ( add 3x to both sides )
11x + 1 = 12 ( subtract 1 from both sides )
11x = 11 ( divide both sides by 11 )
x = 1