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2 years ago

Plz explain

Mathematics

2 answers:

otez555 [7]2 years ago

8 0

Answer: c

Step-by-step explanation: The answer is c because t affects the amount of money sold each day so if there were less tickets sold less money would be made and if more tickets were sold more money would be made.

NeTakaya2 years ago

7 0

Shdjnsbshdudhdndnxnnxnx

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8. The expression below is evaluated when x = 9, y = 3,

Reptile [31]

Answer:

Step-by-step explanation:

First of all substitute the values to where ever you see their corresponding variables to make them multiply.

x = 9

y = 3

z = 2

so we get

8x as 8(9),

7z as 7(2)

2y as 2(3)

then the it's will be

8(9) - 7(2) + 2(3)

which is

72 - 14 + 6

finally we get

4 0

2 years ago

What is this math problem<br> -1/12 - (-3/4)

Ivan

Answer:

-1/12 - (-3/4)

= -1/12 + 3/4

= (-1+9)/12

= 8/12

=2/3

3 0

3 years ago

Explain how to solve -4(1.75 + x) =18

kobusy [5.1K]

Answer:

first change any decimal to a whole. -4(175+x)=18. Then times -4 by 175 and x, -700+ 4x =18. Then add +700 to -700 which equals just 4x ,then add +700 to 18, which is 4x = 718. then divide both sides by 4 and estimate. x= 180

Step-by-step explanation:

8 0

2 years ago

100 POINTS! SOLVE FOR X. PIC ATTACHED. Random answers will be reported.

Romashka-Z-Leto [24]

Answer:

x = 29

Step-by-step explanation:

The angles (2x- 10) and (4x+ 16) are consecutive interior angles and therefore are corresponding

<u>Corresponding angles sum to 180</u>

(2x - 10) + (4x + 16) = 180
6x + 6 = 180
6x = 174
x = 174/6
x = 29

8 0

2 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago