Answer:
20 ≤ y ≤ 70
Step-by-step explanation:
Range is the possible outout values
20 ≤ y ≤ 70
For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
More can be learned about probability distributions at brainly.com/question/24802582
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-7(-1-m)
First: You would distribute your -7 to your -1 and your -m
Note: A positive and a positive makes a negative.
You would get: 7m+7 as your answer
HOPE THIS HELPS! ^_^
Answer:
-2
Step-by-step explanation:
We have to multiply 10 and 
Here we have to distribute the negative sign.
Distributive property = -(a) = -a
Using the above property, we get = 
Now we have to multiply 10 and
= 10 ×
= 
= 
Now we have to divide -10 by 5.
= -2
