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liubo4ka [24]
2 years ago
15

Fill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable , whose possible values

are 0, 1, 3, 4, and 5.

Mathematics
1 answer:
Naddika [18.5K]2 years ago
6 0

For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:

  • P(X = 0) = 0.40.
  • P(X = 1) = 0.04.

<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>

The sum of all the probabilities must be of 1, hence:

P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.

Then, considering the table:

P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1

P(X = 0) + P(X = 1) + 0.56 = 1

P(X = 0) + P(X = 1) = 0.44.

Hence one possible example is:

  • P(X = 0) = 0.40.
  • P(X = 1) = 0.04.

More can be learned about probability distributions at brainly.com/question/24802582

#SPJ1

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