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denis-greek [22]
3 years ago
15

Can someone please help me!!!​

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

Answer:

H. 260

Step-by-step explanation:

We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.

14 tables * 14 students = total students

196 = total students ( for those fourteen tables)

Now we also know that sixteen students can sit on the rest of the cafeteria tables.

We need to find the number of tables can hold sixteen students.

To do this, we'll lead with a simple equation:

18 tables total - 14 tables = # of remaining tables

4 = # of remaining tables

Now we're going to do the same thing we did with the original tables:

4 tables * 16 students = total students

64 = total students

Finally, we add both of the tables max values together:

64 + 196 = 260

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Find three consecutive even numbers whose sum is 1884.
Scilla [17]

Answer:

smallest number=626

middle number=628

larger number=630

Step-by-step explanation:

To find the numbers, let's use n as the variable. Since we know that the numbers are consecutive even numbers, we know that they increase by 2. For example, we could have 2+4+6=12.

Knowing that the consecutive numbers increase by two's, we can use this.

smallest number: n

middle number: n+2

larger number: n+4

All we have to do is add these together and set it equal to 1884.

n+(n+2)+(n+4)=1884          [combine like terms]

3n+6=1884                         [subtract both sides by 6]

3n=1878                              [divide both sides by 3]

n=626

Now that we know n=626, we also know that the other numbers are 626, 628, 630 respectively.

5 0
3 years ago
Decrypt the word DKA if it was encrypted using an alphabetic Caesar shift cipher that starts with shift 5 (mapping A to F), and
pochemuha

Answer:

YET

Step-by-step explanation:

TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.

TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.

D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.

SO, D IS DECRYPTED AS Y

GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.

K IS THEN DECRYPTED AS

K = J - I - H - G - F - E

K IS DECRPYTED AS E

GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS

A = Z - Y - X - W - V - U - T.

THUS, DKA IS DECRYPTED AS YET

5 0
3 years ago
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Answer:

y= \frac{-5}{4}x -4

Step-by-step explanation:

using pt-slope form, we get  y - (-9) = \frac{-5}{4}(x-4). Using the Distributive Property and Addition Propert of Equality, we can simplify this equation into y = \frac{-5}{4}x + 5 by factoring -5/4 into (x-4) and subtracting 9 from both sides.

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zalisa [80]
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Step-by-step explanation:

x =  \frac{30}{7}

6 0
2 years ago
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