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Natali [406]
4 years ago
11

Based upon extensive data from a national high school educational testing program, the standard deviation of national test score

s for mathematics was found to be 120 points. If a sample of 225 students are given the test, what would be the standard error of the mean?
Mathematics
1 answer:
Tomtit [17]4 years ago
6 0

Answer:

8 is the standard error of mean.                                      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 225

Standard deviation = 120

We have to find the standard error of he mean.

Standard error is the ration of standard deviation to square root of sample size.

Formula:

\dfrac{\sigma}{\sqrt{n}} = \dfrac{120}{\sqrt{225}} = 8

Thus, 8 is the standard error of mean.

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Answer:

Sara bought 5 6 penny nails and 3 10 penny nails

Step-by-step explanation:

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3 years ago
If log x+y/5 = 1/2(log x + log y) the find the value of x/y + y/x ?​
V125BC [204]

Given that

log (x+y)/5 =( 1/2) {log x+logy}

We know that

log a+ log b = log ab

⇛log (x+y)/5 =( 1/2) log(xy)

We know that log a^m = m log a

⇛log (x+y)/5 = log (xy)^1/2

⇛log (x+y)/5 = log√(xy)

⇛(x+y)/5 = √(xy)

On squaring both sides then

⇛{ (x+y)/5}^2 = {√(xy)}^2

⇛(x+y)^2/5^2 = xy

⇛(x^2+y^2+2xy)/25 = xy

⇛x^2+y^2+2xy = 25xy

⇛x^2+y^2 = 25xy-2xy

⇛x^2+y^2 = 23xy

⇛( x^2+y^2)/xy = 23

⇛(x^2/xy) +(y^2/xy) = 23

⇛{(x×x)/xy} +{(y×y)/xy} = 23

⇛(x/y)+(y/x) = 23

Therefore, (x/y)+(y/x) = 23

Hence, the value of (x/y)+(y/x) is 23.

4 0
3 years ago
a rectangle has a length of 8ft and a width of 6ft. if its length and width increase by 50% each, what is the area of the new re
Nadya [2.5K]

Answer:

108 ft²

Step-by-step explanation:

Increasing by 50% means multiplying the original quantities by 1.5, that is

100% + 50% = 150% = 1.5 ( 100% is the original dimensions ), thus

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Thus

Area = length × width = 12 × 9 = 108 ft²

3 0
3 years ago
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Crank
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8 0
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How do you write -6 as a inequality
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Answer: Use a bar or a number line. Try my example with -6.

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Simplify:

x > 10

Solved^

3 0
4 years ago
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