9514 1404 393
Answer:
- driver's tank: 30,427 lb
- farmer's tank: 12,811 lb
Step-by-step explanation:
The formula for the volume of a cylinder is ...
V = πr^2·h . . . radius r, height h
The radius of the driver's tank is half its diameter, so is (8 ft)/2 = 4 ft. Then the volume of that tank is ...
V = π(4 ft)^2·(19 ft) = 304π ft^3
Each cubic foot of gasoline has a mass of ...
(1728 in^3/ft^3)(0.0262 lb/in^3) = 45.2736 lb/ft^3
Then the total mass in the driver's full tank is ...
(304π ft^3)(45.2736 lb/ft^3) ≈ 43,238.3 lb
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The farmer's tank is a scaled-down version of the driver's tank. It's volume will be scaled by the cube of the linear scale factor, so will be (2/3)^3 = 8/27 of the volume of the driver's tank.
The farmer's tank will hold a mass of (43,238.3 lb)(8/27) ≈ 12,811 lb.
The amount remaining in the driver's tank is 43,238 -12,811 = 30,427 lb.
Answer:
5y +3
Step-by-step explanation:
3(y + 1) + 2y =
3y +3 +2y =
5y +3
Simply divide your wire by 12 and cut off the excess (as it cannot make a full 12-inch section).
27
÷12=2
So you have two 12-inch sections and an additional 3.4-inch section.
The answer here is C. Let's proof.
Since we are dealing with whole numbers, select a constant for x to satisfy that y will result a whole number.
If x = 1, then the function would be 1 + 4y = 9. Solving for y,
4y = 9 - 1
4y = 8
y = 2
In ordered pair, that is (1,2)
Next, if x = 5, then 5 + 4y = 9. Solving for y,
4y = 9 - 5
4y = 4
y = 1
In ordered pair, that is (5,1).
Lastly, if x = 9, then 9 + 4y = 9. Solving for y,
4y = 9 - 9
y = 0/4
y = 0
In order pair, that is (9,0).
Answer:
Please check the explanation.
Step-by-step explanation:
Finding Domain:
We know that the domain of a function is the set of input or argument values for which the function is real and defined.
From the given graph, it is clear that the starting x-value of the line is x=-2, the closed circle at the starting value of x= -2 means the x-value x=-2 is included.
And the line ends at the x-value x=1 with a closed circle, meaning the ending value of x=1 is also included.
Thus, the domain is:
D: {-2, -1, 0, 1} or D: −2 ≤ x ≤ 1
Finding Range:
We also know that the range of a function is the set of values of the dependent variable for which a function is defined
From the given graph, it is clear that the starting y-value of the line is y=0, the closed circle at the starting value of y = 0 means the y-value y=0 is included.
And the line ends at the y-value y=2 with a closed circle, meaning the ending value of y=2 is also included.
Thus, the range is:
R: {0, 1, 2} or R: 0 ≤ y ≤ 2
