Hello :
cos(3<span>θ) = -1
</span>cos(3θ) = cos(<span>π)
</span>general solution in : R is
3θ = (2k+1)π k in Z
θ = (2k+1)π/3
if θ in <span> [0 , 2</span>π] the solutions are :
k=0 : x = π/3
k=1 : x = π
k=2 : x = 5π/3
Answer: =18g^2−54
Step-by-step explanation:
Answer:
4. (-2 1/2, 4 1/2)
Step-by-step explanation:
Midpoint Formula is (x1+x2)/2, (y1+y2)/2
So (-6+1)/2 , (1+8)/2 = (5)/2, (9)/2 = (2.5,4.5)
And that in fraction form is (-2 1/2, 4 1/2)
Answer:
Equation: f(x)=x²-4x+3
Stretch factor: a=1
Step-by-step explanation:
Notice the x-intercepts are (1,0) and (3,0) which can help us determine the equation by setting their expressions equal to 0 and expanding:
(x-1)(x-3)=0
x²-4x+3=0
Therefore, the equation is f(x)=x²-4x+3 where the stretch factor is a=1
