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2 years ago

What expression factors to 8(x+2)

Mathematics

2 answers:

Scorpion4ik [409]2 years ago

8 0

8(x+2)
8x+16
When you multiply the two together, you get the simplified version.

liq [111]2 years ago

4 0

If you would like to solve 8 * (x + 2), you can do this using the following steps:

8 * (x + 2) = 8 * x + 8 * 2 = 8 * x + 16

The correct result would be 8 * x + 16.

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How would you write one million as a power of 10? Thank you appreciate your help!

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Step-by-step explanation:

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3 years ago

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2 years ago

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Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

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2 years ago

How do you solve for range of exponential function?

FromTheMoon [43]

For any exponential function, f(x) = abx, the range is the set of real numbers above or below the horizontal asymptote, y = d, but does not include d, the value of the asymptote.

Overall, the steps for algebraically finding the range of a function are:
Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).
Find the domain of g(y), and this will be the range of f(x).
If you can't seem to solve for x, then try graphing the function to find the range.

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2 years ago