All categories

3 years ago

What expression factors to 8(x+2)

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

8 0

8(x+2)
8x+16
When you multiply the two together, you get the simplified version.

liq [111]3 years ago

4 0

If you would like to solve 8 * (x + 2), you can do this using the following steps:

8 * (x + 2) = 8 * x + 8 * 2 = 8 * x + 16

The correct result would be 8 * x + 16.

You might be interested in

Two numbers total 86 and have a difference of 12. Find the two numbers.

mestny [16]

Let the two numbers be x and y.

x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________

2x = 98

x = 98/2

x = 49

From x + y = 86

49 + y = 86

y = 86 - 49

y = 37

The numbers are 49 and 37.

4 0

3 years ago

2. Determine which form of a line the given equation is in. Then, determine the slope and y-intercept.

xxMikexx [17]

Answer:

67 the answer is 67 because u add it all up

5 0

3 years ago

Question 5 of 10

Lady_Fox [76]

Answer:

______

x = − 0. 142857

Step-by-step explanation:

7 0

2 years ago

a 12 pound cat is prescribed amoxicillin at 5 mg kg twice a day for 7 Days the oral medication has a concentration of 50 mg ml a

velikii [3]

<span>The first step in determining the answer will need to be to convert the weight from imperial to metric. 12lbs ~ 5.44311kg Then we need to look at the total amount of amoxicillin needed. At 5mg/kg is ~27.5mg twice per day. The concentration is 50mg per ml. Knowing that the cat needs around 55mg, that leads us to 1.1ml daily.</span>

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

3 years ago