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weqwewe [10]
3 years ago
9

a square window has a perimeter of (8x + 12) feet. Write an expression that represents the side length of the window. (in feet)

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0
8x+12=p so you would take away 12 from p making the equation 8x=p-12 and then divide that by 8 so the equation is x= p-12/8 ( x equals p minus 12 over 8)

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Simon has a certain length of fencing to enclose a rectangular area. The function AAA models the rectangle's area (in square met
pav-90 [236]

Answer:

When there is no width, the area is 0m²

Step-by-step explanation:

Expressing the area of a rectangle as a function of its width:

Area of a rectangle = Length * width

Since the area of rectangle is related to the width by the multiplication operatkr. We can conclude from the options given that ; if the value of width = 0 ; the the area of rectangular plot = 0

When x :

Area = Length * width

Area = Length * 0

Area = 0

Area = Length * 0

Aea = 0

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Rksheet
VLD [36.1K]

See below for the terms, coefficients, and constants in the variable expressions

<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>

To determine the terms, coefficients, and constants, we use the following instance:

ax + by + c

Where the variables are x and y

  • Then the terms are ax, by and c
  • The coefficients are a and b
  • The constant is c

Using the above as guide, we have:

A) 2b + 2ac+5

  • Terms: 2b, 2ac, 5
  • Coefficient: 2, 2 and 5
  • Constant 5

B) 34abx + 16y +1

  • Terms: 34abx, 16y, 1
  • Coefficient: 34ab, 16
  • Constant: 1

C) st +4u + v

  • Terms: st, 4u, v
  • Coefficient: 4

D) 14xy + 6

  • Terms: 14xy, 6
  • Coefficient: 14, 6
  • Constant 6

E) 14x + 12y

  • Terms: 14x, 12y
  • Coefficient: 14, 12

F) 3+ 6-7+a

  • Terms: 3, 6, -7, a
  • Coefficient: 1
  • Constant: 3, 6, -7

Read more about terms, coefficients, and constants at:

brainly.com/question/14625487

#SPJ1

5 0
1 year ago
A class of 33 students elected a class treasurer. there were 111votes for candidate a and 15 votes for candidate
Advocard [28]

Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be

11/33 x 100=33.333333...

About 33.333 of the voters voted for candidate a.

3 0
3 years ago
Hi, who wanna talk?<br><br> I'm bored!
skelet666 [1.2K]

Answer:

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3 years ago
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