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TiliK225 [7]
3 years ago
13

6. A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the near

est whole page, how many pages of the magazine are advertisements?
Mathematics
1 answer:
earnstyle [38]3 years ago
7 0

We have (2/3)÷5 = 2/15 advertisments for 1 page;

Then, we have 98 · (2/15) = 12.2(6) advertisments for 98 pages;

The nearest whole page is 12.

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Answer: 20\ cm

Step-by-step explanation:

The first step to solve the exercise is to make the conversion from meters to centimeters.

Since 1\ m=100\ cm, then the dimensions of the wood board in centimeters are:

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Now, you must find the Greatest Common Factor (GCF). The steps are:

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100=2*2*5*5=2^2*5^2\\60=2*2*3*5=2^2*3*5

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Inessa [10]
You need to show the diagram
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erma4kov [3.2K]

Answer:

Step-by-step explanation:

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   [note:  passengers and carriages cancel. Leaving only trains]

(350000)*(1/32)*(1/15) trains       [note: I write this way to paste into MS Excel]

729.1667  trains                 [oh, but don’t just round this number either up or down]

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   730 full trains can carry 730*32*15 = 350400 passengers

Now, we can say that 730 trains are adequate to carry 350000 passengers.

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Answer:

$78.69

Step-by-step explanation:

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Answer:

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