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2 years ago

Solve for a. g= R ———— p (d + a)

Mathematics

1 answer:

maks197457 [2]2 years ago

6 0

Answer:

r/2pdg = a

Step-by-step explanation:

g = R/p(d + a)

g = R/pd + pa

g/r = 1/pd + pa

gpd/r = 1/pa

r/gpd = pa

r/g2pd = a

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Look at the point P on the number line.Which number lines have a point that is equal to pointP? Check all that apply.р

Viktor [21]

In the given Number line the differece between each interval is 10

and the Point P is at -40

Since,

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So, the point is at -30

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1 year ago

(5 x 3) x 2 = 5 x (3 x 2)

vodka [1.7K]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Mama L [17]

Answer:

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Step-by-step explanation:

* Lets explain how to solve the problem

- The fraction m/n has m as a numerator and n as a denominator

- To compare between fractions we must to put all of them with

same denominator

- We can make that by find the lowest common multiple (L.C.M) of

the all denominators

- Ex: The L.C.M of the denominators of these fraction

$\frac{1}{2},\frac{3}{4},\frac{5}{6}$ is 12 because 12 is the first

common multiple of 2 , 4 , 6

- The fractions will be change:

# $\frac{1}{2}=\frac{6}{12}$ ⇒ we multiplied up and down by 6

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# $\frac{3}{4}=\frac{9}{12}$ ⇒ we multiplied up and down by 3

to make the denominator = 12

# $\frac{5}{6}=\frac{10}{12}$ ⇒ we multiplied up and down by 2

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* Lets solve the problem

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∴ The fraction $\frac{7}{8}=\frac{35}{40}$ ⇒ we multiplied up

and down by 5 to make the denominator = 40

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and down by 8 to make the denominator = 40

- Lets find any fraction between $\frac{35}{40}$ and $\frac{24}{40}$

∵ The fraction $\frac{30}{40}$ is between the fractions

$\frac{35}{40}$ and $\frac{24}{40}$

∴ $\frac{35}{40}>\frac{30}{40}>\frac{24}{40}$

- Lets reduce the fraction to its simplest form

∵ The simplest form of $\frac{30}{40}$ is $\frac{3}{4}$

by dividing up and down by 10

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