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3 years ago

Please solve the right triangle below. Round the decimals to the nearest tenth.

Mathematics

1 answer:

aniked [119]3 years ago

7 0

Find $AB$ using Pythagorean Theorem,

$AB=\sqrt{12^2+9^2}=15$ .

$A=\tan^{-1}(12/9)=53.1^{\circ}$ .

$B=\tan^{-1}(9/12)=36.9^{\circ}$ .

Hope this helps.

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A student solved the equation 2x+2=10 using algebra tiles. She incorrectly says the solution is 6 . Solve the equation. What mis

Alex_Xolod [135]

Answer:

she added 2 instead of subtracting it. the answer is x=4

Step-by-step explanation:

10+2=12

12/2=6

7 0

3 years ago

Read 2 more answers

-3(y-5)=24 what is the value of y

Gemiola [76]

Step 1
distribute the -3
-3(y-5)=24
-3y+15=24
step 2
subtract 15 from both sides
-3y =9
Step 3
divide -3 on both sides
y=-3

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2 years ago

Let W be part of the solid sphere of radius 4, centered at the origin, that lies above the plane z = 2. Set up an integral in cy

andriy [413]

Answer:

V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π

Step-by-step explanation:

Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.

So, r = √(R² - z²)

r = √(4² - z²)

r = √(16 - z²)

Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4

Our volume integral in cylindrical coordinates is thus

V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π

4 0

2 years ago

What is 15 percent of 60

maria [59]

Answer:

9 %

Step-by-step explanation:

7 0

2 years ago

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A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce

julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

$Z=\frac{X-\mu}{\sigma}$

We substitute x=161.4 , $\mu=150$ , and $\sigma=20$ to get:

$Z=\frac{161.4-150}{20} \\Z=0.57$

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

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2 years ago