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DiKsa [7]
3 years ago
11

Write the recursive formula for the arithmetic sequence {an}={2.6,4,5.4,6.8,8.2,...}

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

1.4

Step-by-step explanation:

start by subtracting 2.6 and 4 you'll get -1.4 dont mind the negative because it doesn't matter, and now you add 1.4 to each number and that's how you get the next number. like 1.4+5.4=6.8 and 1.4+6.8=8.2, and so on.

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How many zeros are in the simplified expression 4×10×
Lesechka [4]

one zero

hope it helped if i didn't please write back and ill try my best for further explanation

5 0
4 years ago
Read 2 more answers
a person invested $6700 for one year, part at 8%, part at 10%, and the remainder at 12%. the total annual income from these inve
lukranit [14]

Answer:

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

Step-by-step explanation:

step 1

Let

x-----> the amount invested at 8% rate

y-----> the amount invested at 10% rate

z-----> the amount invested at 12% rate

z=(x+y)+300 ----> equation A

x+y+z=6,700 ----> equation B

substitute equation A in equation B

x+y+(x+y+300)=6,700

2x+2y=6,400

x+y=3,200 -----> equation C

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=1\ year\\ P=\$6,700\\ I=\$716

substitute in the formula above

716=x(0.08)+y(0.10)+z(0.12)

substitute equation A

716=x(0.08)+y(0.10)+(x+y+300)(0.12)

716=0.08x+0.10y+0.12x+0.12y+36

716=0.20x+0.22y+36

0.20x+0.22y=680  -----> equation D

step 2

Solve the system of equations

x+y=3,200 -----> equation C

0.20x+0.22y=680  -----> equation D

Solve the system by graphing

The solution is the point (1,200,2,000)

see the attached figure

Find the value of z

z=(x+y)+300

z=(1,200+2,000)+300=3.500

therefore

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

8 0
4 years ago
15 of the 60 vehicles are cars what percent of the vehicles are <br> cars
Komok [63]

Answer:

25 percent

Step-by-step explanation:

to get percent you need a fraction of something over a hundred. To get there, you simplify this to 1/4, then go to 25/100, so 25%

6 0
3 years ago
Read 2 more answers
Radon is a gas produced when radium decays, and it can enter homes where it can be a health threat. Among 180 homes in Hyde Park
mylen [45]

Answer:

We are given that Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels. Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

Claim : the two towns have different rates of unsafe radon levels.

Let p_1 and p_2be the rates of unsafe radon levels of Hyde Park and LaGrange respectively .

H_0:p_1=p_2\\H_a:p_1\neq p_2

Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels

So, n_1=180, y_1=25

Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

So, n_2=230, y_2=50

We will use Comparing Two Proportions

\widehat{p_1}=\frac{y_1}{n_1}

\widehat{p_1}=\frac{25}{180}

\widehat{p_1}=0.1388

\widehat{p_2}=\frac{y_2}{n_2}

\widehat{p_2}=\frac{50}{230}

\widehat{p_2}=0.217

\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{25+50}{180+230}=0.1829

Formula of test statistic :\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}

Substitute the values  

test statistic :\frac{0.138-0.217}{\sqrt{0.1829(1-0.1829)(\frac{1}{180}+\frac{1}{230})}}

test statistic :  −2.053

Refer the z table for p value

p value = 0.0202

α= 0.05

Since p value < α

So, we reject the null hypothesis that the two towns have same rates of unsafe radon levels.

So, Claim is true.

3 0
4 years ago
Evaluate -2x2 y, if x = -3 and y = -1
Gre4nikov [31]
The answer is -12
these are the steps on how to find that 
-2x2y
-2(-3)2(y)
6 times -2
-12
6 0
3 years ago
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