Write the expression as an inequality.
2 answers:
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The slope of the function, f(x) can be determined by choosing two sets of ordered pairs from the table and substituting their values into the slope formula.
Let (x1, y1) = (0, -1)
(x2, y2) = (1, 7)
Plug these values into the slope formula:
m = (y2 - y1)/(x2 - x1)
m = [7 - (-1)] / [1 - 0]
m = (7 + 1) / 1
m = 8/1 or 8.
Therefore, the slope of f(x), m = 8.
The y-intercept of the function, f(x) is given by (0, -1), as it is the point on the graph where it crosses the y-axis. It is also the value of y when x = 0.
The equation of the linear function, f(x) is:
f(x) = 8x - 1.
Given the slope-intercept form, y = mx + b, where m represents the slope of the line, and b represents the y-intercept:
The function, g(x) = 3x - 2 has a slope of 3, and y-intercept of -2.
Comparing the slope and y-intercept of the two functions, f(x) and g(x):
The slope of f(x), m = 8 is greater and steeper than the slope of g(x), m = 3. The y-intercept of f(x), b = -1 is greater than the y-intercept of g(x), b = -2.
Attached is a screenshot of the graph of both lines, including their y-intercepts. The blue line is g(x) = 3x - 2, and the red line is f(x) = 8x - 1.
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Let (x1, y1) = (0, -1)
(x2, y2) = (1, 7)
Plug these values into the slope formula:
m = (y2 - y1)/(x2 - x1)
m = [7 - (-1)] / [1 - 0]
m = (7 + 1) / 1
m = 8/1 or 8.
Therefore, the slope of f(x), m = 8.
The y-intercept of the function, f(x) is given by (0, -1), as it is the point on the graph where it crosses the y-axis. It is also the value of y when x = 0.
The equation of the linear function, f(x) is:
f(x) = 8x - 1.
Given the slope-intercept form, y = mx + b, where m represents the slope of the line, and b represents the y-intercept:
The function, g(x) = 3x - 2 has a slope of 3, and y-intercept of -2.
Comparing the slope and y-intercept of the two functions, f(x) and g(x):
The slope of f(x), m = 8 is greater and steeper than the slope of g(x), m = 3. The y-intercept of f(x), b = -1 is greater than the y-intercept of g(x), b = -2.
Attached is a screenshot of the graph of both lines, including their y-intercepts. The blue line is g(x) = 3x - 2, and the red line is f(x) = 8x - 1.
Please mark my answers as the Brainliest if you find this helpful :)
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
Taken together, we find that (0, 0, 0) appears to be the only critical point on
within the ball. At this point, we have 
.
Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian
with partial derivatives (set to 0)
We then observe that
So, ignoring the critical point we've already found at (0, 0, 0),
So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of
, at which points we get a value of either of 
, with the maximum being the positive value and the minimum being the negative one.
Taken together, we find that (0, 0, 0) appears to be the only critical point on
Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian
with partial derivatives (set to 0)
We then observe that
So, ignoring the critical point we've already found at (0, 0, 0),
So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of