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3 years ago

8

Halle had 15 pounds of sand to give to 6 of her friends for an art project. How many pounds of sand did each friend receive if H

alle divided it evenly? Leave answer as a reduced mixed number with a space between the whole number and the fractional part.

1 answer:

zubka84 [21]3 years ago

7 0

Each friend received 2 1/2 pounds of sand

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Using the number line shown, subtract 1 2/6 from 4 4/6.

Soloha48 [4]

Hey there!

$\bold{1\frac{2}{6}-4\frac{4}{6}}$

$\bold{1\frac{2}{6}=1\frac{1}{3}=\frac{4}{3}}$
$\bold{4\frac{4}{6}=4\frac{2}{3}=\frac{14}{3}}$
Problem becomes: $\bold{\frac{4}{3}-\frac{14}{3}}$
To solve our new problem $\uparrow;\downarrow$
$\bold{4-14=-10}$
The $\bold{3's}$ stay the same because the same
$\bold{\rightarrow=\frac{-10}{3}}$
$\boxed{\boxed{\bold{Answer:\frac{-10}{3} (or)=-3\frac{1}{3}}}}$

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3 years ago

Depending on the car and the additional features, a convertible sports car can cost between $19,028 and $370,790. Write two ineq

liraira [26]

Cost of Car= C

$19,028 <span>≥</span><span> C ≤ $370,790
</span>
The cost of the sports car is greater than or equal to $19, 028 and less than or equal to $370,790.

6 0

3 years ago

Evaluate c−d if c=1 and2/5 and d=5/6 . Express your answer in simplest form.

Andrews [41]

Answer:

$\frac{17}{30}$

Step-by-step explanation:

→ Substitute in the numbers

$1\frac{2}{5} -\frac{5}{6}$

→ Simplify

$1\frac{2}{5} -\frac{5}{6}=\frac{7}{5} -\frac{5}{6}=\frac{42}{30} -\frac{25}{30} =\frac{17}{30}$

5 0

2 years ago

Please help with this

snow_lady [41]

Answer:

B. $- \frac{9}{8}$

Step-by-step explanation:

$\huge\frac{ - 2 {a}^{ - 3} {b}^{2} }{a} \\ \\ \huge = \frac{ - 2 {b}^{2} }{a \times{a}^{ 3} } \\ \\ \huge = \frac{ - 2 {b}^{2} }{{a}^{ 4} } \\ \\ \huge = \frac{ - 2 \times {3}^{2} }{ {( - 2)}^{4} } \\ \\ \huge= \frac{ - 2 \times 9}{16} \\ \\ \huge \red{= - \frac{9}{8} }$

8 0

3 years ago

The figure shows part of the concrete slab which is used to make drains and its cross-section. it is made up of a cuboid of dime

Arlecino [84]

(i) The area of the cross section ABCDEFG is 1771.6cm³

(ii) The volume of the concrete lab is 212592 cm³

(iii) the total surface area of the concrete slab is 30284 cm²

(iv) The mass of the concrete slab is 40746.8 kg/m³.

Given, dimensions are 120 cm by 60 cm by

40 cm.

(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2

= 1771.6 cm³

(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120

= 212592 cm³

(iii) The total surface area is:

=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120

= 30284 cm²

(iv) Mass of the concrete slab given density is 2300 kg/m³

Mass = Volume × density

Mass = 17.716 m³ × 2300

= 40746.8 kg/m³

Hence we get the mass as 40746.8 kg/m³.

Learn more about "Mensuration" here-

brainly.com/question/26398444

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2 years ago