Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:the ratio of the % increase has a different numerator from decrease
Step-by-step explanation:
Because this is a second degree equation you will have 2 solutions. When you take the square root of a number you have to account for both the positive and negative roots. Since the square root of 289 is 17 then your solutions are +17 and -17.
Answer: 2, 3, 6, 8 (top) 1.40, 2.10 4.20, 5.60 (bottom)
Step-by-step explanation: If 1 pound = 0.70, then 2*0.70=1.40. 2.10 divided by 0.70=3. 0.70*6=4.20. 0.70*8=5.60.
I = PRT
P (principal) = 6000
R (rate) = 3.7%.....u need decimal form = 0.037
T (time) = 5
I = (6000)(0.037)(5)
I = 1110.00 <===
u dont need years as a decimal...u need rate as a decimal
