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zzz [600]
4 years ago
5

Each leg of 45 degree -45 degree -90 degree triangle measure 12 cm what is the length of the hypotenuse

Mathematics
1 answer:
Yuri [45]4 years ago
3 0
A = b = 12 cm


<span>Pythagorean theorem
</span>
a^2+b^2=c^2\\\\ c^2=a^2+a^2\\\\ c^2=2a^2\\\\ c=\sqrt{2a^2}

c=a\sqrt2 formula

c=12\sqrt{2} \ (cm) <-- Answer
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Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

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\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

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\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

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3 years ago
Which combination of three side lengths will NOT form a triangle?
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because the side length of triangle does not obey triangle inequality theorem.

The triangle inequality theorem:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

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