Answer:
i dont know
Step-by-step explanation:
that is too hard
Answer:
The answer to your question is f = 10.35 in
Step-by-step explanation:
Data
Proportion = 4:9
height 1 = 4.6 in
height 2 = f
Process
1.- Write the proportion

2.- Solve for f



4f = 41.4

f = 10.35 in
Answer:
The brother is likely wrong.
Step-by-step explanation:
The range of the vehicle with a full tank is ...
(13.5 gal/tank)(25 mi/gal) = 337.5 mi/tank
You have 1/4 tank, so your range is ...
(337.5 mi/tank)(1/4 tank) = 84.375 mi
If you make the 85 mile distance, it will be because you achieved gas mileage better than average and/or your gas gauge gives you some cushion.
Unit analysis says you do not have the necessary range.
f(x) = 57 (19)^(x-4)
The domain is the input or x values
what are the allowed x values
we can put in any values of x we want and the function still works
Domain: all real values
The range is the output or the y values
It will always be greater than 0
Range: y> 0 or all positive real numbers
Answer:
it would be 5%
Step-by-step explanation:
10%÷2=0.05%