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NikAS [45]
3 years ago
15

To estimate the number of people in Springfield, population 10,000, who have a swimming pool in their backyard, 250 people were

interviewed. Of those polled, 119 had a swimming pool. How many people in the city might one expect to have a swimming pool? (Round to the nearest whole number, if necessary.)
Mathematics
1 answer:
amid [387]3 years ago
5 0
Multiply 119 by 40 to get 4760 people who have a pool. 
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Natalie invested $40,000 in an account paying an interest rate of 8 % compounded
NARA [144]

Answer:

8000

Step-by-step explanation:

Natalie

Divide 40k by 2 to get 20k and divide 20k by 5 to get 4k we are at 10%

4k / 5 = 800 that means that every 2% is 800 now we multiply by 4x

To get 8% and we get 3200 and multiply by 20 representing the yrs

3200 x 20 = 64k + 40+ = 104k

Mackenzie

40k divide by 2 to get 50% 40k / 2 = 20k and now we divide by 5 to get 10% 20k / 5 = 4k now we divide by 10 to get the amount of each percents worth 4k / 10 = 400 we multiply by 9 to get the compounded interest

400 x 9 = 3600 multiply by 20 to get the compounded daily investment after 20yrs 3600 x 20 = 72k + 40k = 112k

112k - 104k = 8k

5 0
2 years ago
What is the value of x​
Alenkasestr [34]

Answer:

68

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help with this pleaseee
saw5 [17]

Answer:

CED=126

Step-by-step explanation:

The total of all 3 angles should be 180

so:

180-38-16 (ABC is equal to ECD)

180-38-16=126

126=CED

5 0
3 years ago
Read 2 more answers
Hailey and Kacie are selling candles to raise money. • Hailey is selling candles for $4 each and has already raised $160. • Kaci
masya89 [10]

Answer:

160+4h=70+7k

Step-by-step explanation:

h(160))

k(70)

4h=7k

3 0
3 years ago
Read 2 more answers
If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?
vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

  • Not all items fit
  • No matter the order
  • Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

C=\frac{m!}{n!*(m-n)!}

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

In this case:

  • n: 3
  • m: 11

Replacing:

C=\frac{11!}{3!*(11-3)!}

Solving:

C=\frac{11!}{3!*8!}

being:

  • 3!=3*2*1=6
  • 8!=8*7*6*5*4*3*2*1=40,320
  • 11!=39,916,800

So:

C=\frac{39,916,800}{6*40,320}

C= 165

<u><em>165 different teams of 3 students can be formed for competitions</em></u>

3 0
3 years ago
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