We have f(x) = 0;
Then x^2 - 1 - 2x - 2 = 0;
(x - 1)(x + 1) - 2(x + 1) = 0;
(x + 1)(x - 1 - 2) = 0;
(x + 1)(x - 3) = 0;
x + 1 = 0 or x - 3 = 0;
x = -1 or x = 3;
The zeroes of f are -1 and 3.
4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0
where y' = dy/dx
8x + 5xy' +5y -2yy' = 0
combining y' terms
y' (5x-2y) +8x +5y = 0
y'(5x-2y) = -(8x+5y)
dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)
Answer:
<h2>Option 2 is the right answer.</h2>
Step-by-step explanation:
We need to check if the two characteristics, <u>having blue eyes and being deaf are independent of each other or not</u>.
The above two characteristics will be independent if ![[Probability of being deaf with blue eyes] = {Probability of being deaf } {Probability of having blue eyes}](https://tex.z-dn.net/?f=%5BProbability%20of%20being%20deaf%20with%20blue%20eyes%5D%20%3D%20%7BProbability%20of%20being%20deaf%20%7D%20%7BProbability%20of%20having%20blue%20eyes%7D)
Now, the probability of having blue eyes is
.
The probability that the Dalmatians will be deaf is
.
The probability of being deaf with blue eyes is
.
Since, 38 is not equals to 42, the two characteristics are not independent.
We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:

For air-raid siren we have:

For jet engine noise we have:

To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
Answer:
How may pandas were born in 2006
Step-by-step explanation: