The distance of the road junction form Timpson is given as 21.57 miles.
<h3>We have to solve this using the Pythagoras theorem method</h3>
We have AT = 
√60² + 12² = 12√26
∠TMG = LN = 90 degrees
Therefore we have the system
When we cross multiply we would have to solve for TM
TM = 21.57 miles
Hence the distance of the road junction form Timpson is given as 21.57 miles.
Read more on distance here:
brainly.com/question/17273444
#SPJ1
The math club could rent the room for up to 8 hours. I have also attached a picture of the work in case you need it.
0 = 2x^2 + 5x -3
0 = (2x-1)*(x+3)
2x-1=0 and x+3=0
X= 1/2 and x = -3
Y= 2(0)^2 + 5(0) - 3
Y = -3
Answer:
25%
Step-by-step explanation:
120$:100%=90$:x$
120x=100x90
120x=9000
9000 divided by 120
75
Answer:
The set of transformation would prove ΔEFG ~ ΔGHI is "Reflect ΔGHI
over x = −2, and dilate ΔG′H′I′ by a scale factor of 2 from point G" ⇒
last answer
Step-by-step explanation:
