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Anika [276]
2 years ago
13

Over summer, Jackie played video games 3 hours per day. When school begin in the fall, she was only allowed to play video games

for half an hour per day. What is the percent decrease? Round to the nearest percent
Mathematics
1 answer:
lesya [120]2 years ago
6 0
30. minutes off the game
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Add and simplify
Tanya [424]

Answer:

Your 1st answer is correct

Step-by-step explanation:

\frac{1}{(x - 1)}  -  \frac{3}{(1 - x)}   + 2

\frac{1}{(x - 1)}  -  \frac{3}{ - (x - 1)}  + 2

\frac{1}{(x - 1)}   +  \frac{3}{(x - 1)}  + 2

\frac{4}{(x - 1)}  + 2

\frac{4 + 2(x - 1)}{x - 1}

\frac{4 + 2x - 2}{x - 1}

= \frac{2x  + 2}{x - 1}

=  \frac{2(x + 1)}{x - 1}

6 0
2 years ago
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
3 years ago
Help I’m in 5th 14 question
shutvik [7]
You would be right with 26 because the absolute value of -30 is 30 then you subtract 56-30 and get 26 which is the remaining temp you need to get to 56.
3 0
2 years ago
What statements are true about the ordered pair (7,19) and the system of equations?
Tju [1.3M]

Answer:C


Step-by-step explanation:


3 0
3 years ago
3x + ky = 8
djyliett [7]

Answer:

a) 3x + ky = 8

ky = 8 - 3x

x – 2ky = 5

x - 2(8 - 3x) = 5

x - 16 + 6x = 5

7x = 21

x = 3 (shown)

b) x-2ky = 5

sub x = 3, y = 1/2

3-2k(1/2) = 5

-2k = 2

k = -1

3 0
2 years ago
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