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3 years ago

Is this a parallelogram, rectangle, rhombus, and/or square and how

Mathematics

1 answer:

NeTakaya3 years ago

8 0

-A rectangle is a four-sided shape each angle is a right angle.

-A rhombus is a four-sided figure and all sides have equal length. Opposite sides are parallel and opposite angles are equal.

-A square has equal sides and every angle is a right angle. Opposite sides are parallel.

-A parallelogram has opposite sides parallel and the sides lengths are the same. Opposite angles are equal

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Triangle ABC is congruent with triangle CDA Find the value of the pronumeral x.

brilliants [131]

Answer:

x = 25

Step-by-step explanation:

Since the triangles are congruent then corresponding angles are congruent.

That is ∠ D and ∠ B are corresponding angles and congruent, thus

4x - 20 = 2x + 30 ( subtract 2x from both sides )

2x - 20 = 30 ( add 20 to both sides )

2x = 50 ( divide both sides by 2 )

x = 25

6 0

3 years ago

Help what is x When x^5 is 225

Rufina [12.5K]

Answer:

Solution given:

x^5=225

we have

x= $\sqrt[5]{225}$

x=2.9541

7 0

3 years ago

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

$x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

3 years ago

Identify the zeros of the graphed function.

Sever21 [200]

Answer:

A I think this is it

Step-by-step explanation:

Hope this helps :) :)

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2 years ago

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1,840 mL = ____ L WHAT DOES L EQUAL PLZ HELP!!!

sweet-ann [11.9K]

It equals 1.84 liters

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3 years ago

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