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valentina_108 [34]
3 years ago
13

Is this a parallelogram, rectangle, rhombus, and/or square and how

Mathematics
1 answer:
NeTakaya3 years ago
8 0
-A rectangle<span> is a four-sided shape each angle is a </span>right angle<span>.
</span>

-A rhombus is a four-sided figure and all sides have equal length. Opposite sides are parallel and opposite angles are equal.

-A square has equal sides and every angle is a right angle. Opposite sides are parallel.

-A parallelogram<span> has opposite sides parallel and the sides lengths are the same. Opposite angles are equal </span>

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To the nearest hundredth, what is the value of x?
Drupady [299]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ cos41 = x/55

x = cos41 x 55

x = 41.50902

The correct option would be 41.51

<h3><u>✽</u></h3>

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3 years ago
Read 2 more answers
HELP PLEASE ASAO I WILL MARK BRAINLIEST
denpristay [2]

Answer:

D)

Step-by-step explanation:

3 0
3 years ago
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The graph of is the widest.
Vlad1618 [11]

By critically observing and comparing the functions for the given graphs, we can logically deduce that the widest graph is: "Function 1: y = 0.25x²."

<h3>How to determine the widest graph?</h3>

In Geometry, a graph which has the smallest positive coefficient of x² in absolute value is generally considered as the widest graph while the graph with the largest positive coefficient of x² in absolute value is the narrowest graph.

By critically observing and comparing the functions for the given graphs, we can logically deduce that "Function 1: y = 0.25x²" is the widest.

Read more on widest graph here: brainly.com/question/11447260

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Complete Question:

Compare the graphs of the functions listed below.

Function 1: y = 0.25x²

Function 2: y = 4x²

Function 3: y = -½x²

Function 4: y = -16x²

The graph of ______ is the widest?

4 0
2 years ago
An object is launched at 28 meters per second (m/s) from a 336-meter tall platform. The equation for the object's height s at ti
kondaur [170]

Answer:343 m

Step-by-step explanation:

Given

launch velocity of object is u=28\ m/s

height of Platform h=336\ m

height of object is given by

s(t)=-7t^2+14t+336

For maximum height velocity of object is zero

i.e. \frac{ds}{dt}=0

\frac{ds}{dt}=-14t+14+0=0

t=\frac{14}{14}=1\ s

Therefore after 1 sec object achieves maximum height

s(1)=-7(1)+14(1)+336

s(1)=343\ m

3 0
4 years ago
PLEASE HELP!!!!! WILL MARK AS BRAINLIEST
Zepler [3.9K]
F(-3)=-3^2-2
=9-2
=7
Therefore your answer is 7
Hope this helps
7 0
4 years ago
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