Answer:
sin=The sin of an acute angle is defined in the context of a right triangle.
csc= The length of the hypotenuse divided by the length of the side opposite the angle.
cos= The length of the adjacent side divided by the length of the hypotenuse.
sec 0=The ratio of the length of the hypotenuse to the length of the adjacent side is the secant of an angle in a right-angled triangle.
tan A=In any right triangle, the tangent of an angle is the length of the opposite side (O) divided by the length of the adjacent side (A).
cotA= In a right triangle, the cotangent of an angle is the length of the adjacent side divided by the length of the opposite side.
Step-by-step explanation:
Answer:
A, B, C, D, F, G
Step-by-step explanation:
A. In order to stop overpayment when your account balance is low, some banks do require a low minimum balance so you don't use more money than you have
B. You can withdraw funds from a checking account easily by using an ATM or go into the bank.
C. There are many different kinds of checking accounts designed for specific activities.
D. One type of account is actually a Money Market account.
F. Some checking account can be joint so 2 or more people can access it (like wife and husband).
G. If you do overpay on your account, you will have to pay penalties for overspending.
E is incorrect because there are some few checking accounts that earn interest (very few).
H is incorrect because some banks require fees and restrictions.
The equation of a circle is defined by:
(x-h)^2+(y-k)^2=r^2
Where (h,k) s the center and r is the radius.
We can translate the word problem into (x+2)^2+(y-8)^2=16
:)
Answer:
NOT a function!
Step-by-step explanation:
A function is a relation where each input has only one and ONLY one output. For example, for the number 2 in a relation, that number 2 can only have one other y value it is paired with, it can not have more than one.
For example, in this problem the number 2 is stated twice. One set has (2, -8) and (2, 8), so that means this input has more than one output. Therefore, this relation is NOT a function.
Hope this helps and please mark brainliest if possible :0
Any questions please put in the comments.
