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SOVA2 [1]
4 years ago
9

How cobalt can be produced from aqueous cobalt sulphate?​

Chemistry
1 answer:
lisov135 [29]4 years ago
4 0
Using a displacement reaction we can put a more reactive metal into cobalt sulphate of where the more reactive metal (such as zinc, aluminium or magnesium) will displace cobalt out of the solution leaving the elemental form of cobalt metal deposit left in a solution of (whatever metal you chose) sulphate.
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Suppose the formation of nitryl fluoride proceeds by the following mechanism: step elementary reaction rate constant (g) (g) (g)
ziro4ka [17]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a

  2NO_2 _{(g)} +  F_2_{(g)} ---->  2NO_2 F_{(g)}

b

  r = \frac{ k [NO_2]^2 [F_2]}{[NO_2F]}

Explanation:

      From the question we are told that

          The formation mechanism is  

                      NO_2_{(g)} + F_2 _{(g)} ----> NO_2 F_{(g)} + F_{(g)}

                      F_{(g)} +  NO_2 _{(g)} ---> NO_2 F_{(g)}

The overall balanced equation is

              2NO_2 _{(g)} +  F_2_{(g)} ---->  2NO_2 F_{(g)}

We combined the first reactant and the last product and the balanced the number of mole

     The observable rate law is

                 r = \frac{ k [NO_2]^2 [F_2]}{[NO_2F]}

This rate law is derived from the balanced chemical equation

     

6 0
3 years ago
Need help ASAP... The diagram shows a box in the periodic table.. what is the atomic number of the element??​
ad-work [718]
The atomic number is 15
4 0
3 years ago
The graph above shows the progress of a chemical reaction. Based on the graph, which of the following is true?
Helen [10]
I believe the answers b
6 0
4 years ago
Read 2 more answers
4. If you put 1 mL of coffee into 9 mL of water, how much was the coffee diluted?
garri49 [273]

1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!

7 0
3 years ago
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A car travels 2.5 hours in a Northern direction for 300km. Determine the cats speed and velocity
nika2105 [10]

Answer:

Velocity = 120 km/h in north

Speed  =  120 km/h

Explanation:

Given data:

Distance = 300 km north

Time taken = 2.5 hr

Speed and velocity = ?

Solution:

Speed = distance / time

Speed  = 300 km / 2.5 h

Speed  =  120 km/h

Velocity = change in position / change in time

Velocity = 300 km north /  2.5 hr

Velocity = 120 km/h in north

3 0
3 years ago
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