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Tema [17]
3 years ago
11

If sulfur gained another electron, would its charge be positive or negative?

Chemistry
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

<u><em>AS WE KNOW THAT</em></u> , when non-metallic elements gain electrons to form anions, SO sulphur is non metal and have the capacity to gain two electrons as lies in 6th group so it can gain electron and become sulphide ion(S-).

<h3><u><em>Thanks for asking question</em></u></h3>

Explanation:

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true or false einsteins equation implies that a large amount of mass can be converted into a small amount of energy
77julia77 [94]

the answer t this question is true



4 0
3 years ago
Read 2 more answers
Treatment of gold metal with brf3 and kf produces br2 and kauf4, a salt of gold. part a identify the oxidizing agent in this rea
tankabanditka [31]
Let's write the reaction first:

<span>2 Au + 2 BrF</span>₃<span> + 2 KF → 2 KAuF</span>₄<span> + Br</span>₂<span> 
</span>
To know which of the substances is the oxidizing agent, calculate the oxidation numbers of each element before and after the reaction. If the element's oxidation number decreases, then that is the oxidation agent. Let's calculate Br.

BrF₃: x + 3(-1) = 0; x = +3
Br₂: 0 (for any elemental form, oxidation number is 0)

The oxidation number is reduced from +3 to 0. <em>Thus, BrF₃ is the oxidizing agent.</em>
5 0
4 years ago
25) If an object’s density is greater than 1.00 g/mL, it will ______________ in water.
NeTakaya

Answer:

1- Option A = Sink

2- Option B = Float

Explanation:

1- If an object’s density is greater than 1.00 g/mL, it will sink in water.

For example, the density of aluminum is 2.7g/cm³. That is why it will sink in water.

2- If an object’s density is less than 1.00 g/mL, it will float in water.

For example, the density of oak is 0.7 g/cm³. That is why oak will float in water.

3-  Given data:

Mass, m = 50 g  

Volume, v = 10 cm3 ( 1ml = 1cm3)

Formula of density :          

Density = mass/ volume

          d = m/v

          d = 50g/10cm3

          d = 5 g/cm3

           

7 0
3 years ago
Calculate the displacement (the total volume of the cylinder through which the piston move) of a 5.70L automobile engine in cubi
Novay_Z [31]

Answer:

348 inches³

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From our previous knowledge of  units conversion:

We know that 1000 cm³ makes 1 Liter.

Thus, for  a 5.70 L automobile engine in cubic meters will be:

= 5.70 × 1000 cm³

= 5700 cm³

Now, the displacement of the automobile in cubic inches provided that 1 inch = 2.534 cm is:

⇒ 5700× (1/ (2.54)³) in³

= 5700×0.0610 in³

= 347.7 in³

≅ 348 inches³

4 0
4 years ago
a student balanced the chemical equation for the reaction of magnesium with oxygen by writing Mg + O2 ----&gt; MgO2. What is wro
egoroff_w [7]

Answer:

Explanation:

Magnesium when it oxidizes has a valence of 2.

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So Mg and O2 will form something, but what? The answer is MgO

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To balance this equation, you need 2 Magnesiums on the right and 2 Oxygens also on the right. The left will need a  two Magnesiums.

The balanced equation will be

2Mg + O2 ====> 2MgO

6 0
4 years ago
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