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Simora [160]
3 years ago
6

Two trains leave the station at the same time, one heading west and the other east. The westbound train travels 14 miles per hou

r slower than the eastbound train. If the two trains are 900 miles apart after 5 hours, what is the rate of the westbound train? Don't do any rounding. Urgent!
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

The answer to your question is 166 mi/h

Step-by-step explanation:

Data

ve = rate eastbound train

vw = rate westbound train = ve - 14

distance = d = 900 mi

time = t = 5 h

Formula

v = \frac{distance}{time} = \frac{d}{t}

Substitution and simplification

ve = \frac{900}{5} = 180 mi/h

Now, substitute this value in the equation of vw

vw = 180 - 14

Result

vw = 166 mi/h

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3 years ago
Judy spent 3 hours driving 165 miles She thinks
sasho [114]

Step-by-step explanation:

she drove already 165 miles.

she will reach her destination, if she drives 4 more hours by going 65 miles/hour.

that would mean she would travel

65×4 = 260 miles

in these 4 hours.

so, the total trip is then 165 + 260 = 425 miles.

but what I find strange is that your teacher specified how long it took her to drive the first 165 miles.

as you can see above, it would make no difference for the calculation of the total trip length in miles.

this is either an attempt to confuse us, or the message is that Judy has to achieve an average of 65 miles/hour for the whole trip, and the problem definition was just imperfectly phrased.

if that is the case, then things look a bit different, as her average speed was only 165/3 = 55 miles/hour for the first 3 hours and 165 miles.

so,

(165 + x)/(3 + 4) hours = 65/hour

(165 + x)/7 hours = 65/hour

165 + x = 65 × 7 hours / hour = 65×7 = 455 miles

x = 455 - 165 = 290 miles

she would have to go

290 miles / 4 hours = 72.5 miles/hour

for these next 4 hours (and 290 miles) to reach an overall average speed of 65 miles/hour.

and the total trip would be then

165 + 290 = 455 miles

I am not sure, which your teacher wants here.

65 miles/hour average speed just for the next 4 hours, or to speed up that much for the next 4 hours that the overall trip average is then 65 miles/hour.

again, the phrasing of the problem definition suggests the first case, but the fact that the travel time for the first part of the trip is given could suggest the second case (as this information is not needed for the first case).

6 0
2 years ago
Plz help ASAP, without using algebra! Tysm!!!
nadya68 [22]
The total travelled for the first five hours eould be 450 km and divided by three leaves 150 km per 1/5 of his journey. travelling at 75 km per hour, it would take 4 hours to get through the remaining 300 km for him trip leaving a total time of 9 hours of traveling
5 0
3 years ago
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