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Simora [160]
3 years ago
6

Two trains leave the station at the same time, one heading west and the other east. The westbound train travels 14 miles per hou

r slower than the eastbound train. If the two trains are 900 miles apart after 5 hours, what is the rate of the westbound train? Don't do any rounding. Urgent!
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

The answer to your question is 166 mi/h

Step-by-step explanation:

Data

ve = rate eastbound train

vw = rate westbound train = ve - 14

distance = d = 900 mi

time = t = 5 h

Formula

v = \frac{distance}{time} = \frac{d}{t}

Substitution and simplification

ve = \frac{900}{5} = 180 mi/h

Now, substitute this value in the equation of vw

vw = 180 - 14

Result

vw = 166 mi/h

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Svetradugi [14.3K]
2m+5=5(m-7)-3m
first, use distributive property...
2m+5=5m-35-3m
next, combine like terms on the right side...
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2 years ago
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Can someone solve this
marysya [2.9K]

From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325  See explanation below.

<h3>

What are the step by steps solution to the questions above?</h3>

First, lets us restate the question properly. We have

Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

Note that there are three equals signs. So lets divide the problem according and solve for the different parts.

Lets   1 - ((6*12+6)/80)²  ............A

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C

Solving for A we have

1 - (78/80)²

= 1 - (0.975)²

= 1 - 0.950625

A = 0.049375


Solving for B we have

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)

= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625

B = -8.050625

Solving for C we have

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144

= 0.0325


In summary we can state that:

A = 0.049375

B =  -8.050625

C = 0.0325

Given that there were no abstract quantities, we can state that

Pr = A ≠ B ≠C or

Pr = 0.049375 ≠ -8.050625 ≠ 0.0325

Learn more about equations with equal signs at

brainly.com/question/18924248
#SPJ1

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Math test! i need help!
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Answer:

First option

Step-by-step explanation:

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