Is there a give area for the triangle?
Answer:
![{27}^{ \frac{1}{3} } = \sqrt[3]{27} = \sqrt[3]{3 \times 3 \times 3} = \boxed{ 3}✓](https://tex.z-dn.net/?f=%20%7B27%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B3%20%5Ctimes%203%20%5Ctimes%203%7D%20%20%3D%20%5Cboxed%7B%203%7D%E2%9C%93)
<h3>3. <em><u>3</u></em> is the right answer.</h3>
<h3>
Answer: f( h(x) ) = 2x - 4</h3>
Work Shown:
f(x) = x - 7
f( h(x) ) = h(x) - 7
f( h(x) ) = 2x+3 - 7
f( h(x) ) = 2x - 4
Explanation:
In the second step, I replaced every x with h(x). In the next step, I replaced the h(x) on the right hand side with 2x+3. From there I combined like terms.
72 is 266.666666667% of 27
Answer:
<h2>VU=16</h2><h2>x=2</h2>
Step-by-step explanation:
lets solve the problem 7x+2=3x+10
subtract 3x from 7x
4x+2=10
subtract 2 from 10
4x=8
divide both sides by 4
x=2
to find VU plug in 2 for x so...
3(2)+10
6+10
16
I hope this helped you :)