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2 years ago

Please help me... there will be 7 more questions where that came from

Mathematics

1 answer:

Aleksandr [31]2 years ago

6 0

168 students because 28% of 600 is 168.

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Not sure how to do this. Help is much appreciated. :D

Free_Kalibri [48]

Answer:

m = √n/3 -k

Step-by-step explanation:

√n = 3(k + m)

=> √n/3 = k + m

∴ m = √n/3 -k

Hope this helps!!

6 0

2 years ago

A school has a new flag that must be flown at last 52 feet high The current flagpole is 14 m tall How many meters taller does th

ohaa [14]

To start with, convert 52 feet into metres
1 Feet= 0.3048
52 feet= ?
The number of meters= 52*0.3048
The number of meters= 15.8496 metres

The school need to add a further 1.8496 metres

6 0

3 years ago

Which expression is equivalent to 7/2h -3(5h-1/2) ?

docker41 [41]

Another expression that is equivalent to 7/2h-3(5h-1/2) is -23/2h+3/2

8 0

3 years ago

2x -2 = -200 <br><br><br> whats the value of x

Elden [556K]

Answer:

Step-by-step explanation:

2x - 2 = - 200

Bringing like terms on one side

2x = - 200 + 2 = - 198

2x = - 198

x = - 198/2 = - 99

4 0

2 years ago

Read 2 more answers

i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%

Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

$\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}$

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

$\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}$

Thus, the required probability is 13.98% approximately.

Theref

7 0

1 year ago