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3 years ago

A distribution is positively skewed if which of these statements is true about the density curve that represents it?

Mathematics

2 answers:

UkoKoshka [18]3 years ago

8 0

<span>The right tail is longer than the left.</span>

mylen [45]3 years ago

6 0

Answer: the left tail is longer that the right -APEX

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Find two algebraic expressions for the area of each figure. First, regard the figure as one large rectangle, and then regard the

lapo4ka [179]

Area = length * width for a rectangle or square
Total area = (t+5)(t+3)
the rest of the areas can be seen here
http://prntscr.com/dc7jdg

7 0

3 years ago

The indicated function y1(x is a solution of the given differential equation. use reduction of order or formula (5 in section 4.

Taya2010 [7]

Given a solution $y_1(x)=\ln x$ , we can attempt to find a solution of the form $y_2(x)=v(x)y_1(x)$ . We have derivatives

$y_2=v\ln x$
${y_2}'=v'\ln x+\dfrac vx$
${y_2}''=v''\ln x+\dfrac{v'}x+\dfrac{v'x-v}{x^2}=v''\ln x+\dfrac{2v'}x-\dfrac v{x^2}$

Substituting into the ODE, we get

$v''x\ln x+2v'-\dfrac vx+v'\ln x+\dfrac vx=0$
$v''x\ln x+(2+\ln x)v'=0$

Setting $w=v'$ , we end up with the linear ODE

$w'x\ln x+(2+\ln x)w=0$

Multiplying both sides by $\ln x$ , we have

$w' x(\ln x)^2+(2\ln x+(\ln x)^2)w=0$

and noting that

$\dfrac{\mathrm d}{\mathrm dx}\left[x(\ln x)^2\right]=(\ln x)^2+\dfrac{2x\ln x}x=(\ln x)^2+2\ln x$

we can write the ODE as

$\dfrac{\mathrm d}{\mathrm dx}\left[wx(\ln x)^2\right]=0$

Integrating both sides with respect to $x$ , we get

$wx(\ln x)^2=C_1$
$w=\dfrac{C_1}{x(\ln x)^2}$

Now solve for $v$ :

$v'=\dfrac{C_1}{x(\ln x)^2}$
$v=-\dfrac{C_1}{\ln x}+C_2$

So you have

$y_2=v\ln x=-C_1+C_2\ln x$

and given that $y_1=\ln x$ , the second term in $y_2$ is already taken into account in the solution set, which means that $y_2=1$ , i.e. any constant solution is in the solution set.

4 0

3 years ago

HELPP PLEASE!!!!!!<br> (Will give 15 points for right Answer)!!!!

VMariaS [17]

Answer:

Step-by-step explanation:

The parallel sides must be the same length.

2x-6 = x+3

2x-x-6-3 = 0

x - 9 = 0

x = 9

x + 3 and 2x - 6 are both 12

8 0

3 years ago

Work out the balance for £5000 invested for 5 years at 7% per annum

zvonat [6]

Given:
Principal : 5,000
Interest rate : 7% per annum
Term : 5 years

Simple interest is computed by multiplying the principal, the interest rate, and the term.

Simple Interest = Principal * interest rate * term

S.I. = 5,000 * 7% * 5years
S.I. = 350 * 5 years
S.I. = 1,750

An investment of 5,000 will earn a total of 1,750 within 5 years at 7% per annum.

7 0

3 years ago

Which is the equation of the parabola?

dimaraw [331]

Answer: y = one sixteenth(x − 4)^2 + 2

Step-by-step explanation:

If the parabola is written as:

y = a*x^2 + b*x + c

then if the graph opens up, then a must be positive, so we can discard the third and fourth options, we remain with:

y = 1/6*(x - 4)^2 + 2 = 1/6x^2 - (8/6)*x + (16/6 + 2)

y = 1/6*(x + 4)^2 - 2 = 1/6x^2 + (8/6)*x + (16/6 - 2)

the vertex (4, 2)

then

x = -b/2a = 4.

this means that a and b must be of different sign, then the only correct option can be:

y = 1/6*(x - 4)^2 + 2 = 1/6x^2 - (8/6)*x + (16/6 + 2)

where:

x-vertex = (8/6)/(2/6) = 4 as we wanted.

when we evaluate this function in x = 4 we get

y = 1/6*( 4 - 4)^2 + 2 = 2.

So the correct option must be: y = one sixteenth(x − 4)2 + 2

6 0

3 years ago