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3 years ago

5. Fatima likes to watch movies and decides to sign up for a movie subscription that will allow

1 answer:

6 0

If you’re looking for an equation for both of these, Bob’s rentals would be 20+2m and Bella’s would just be 6m. If you are trying to figure out how many movies it would take to be the same, set up the equation 20+2m=6m and solve. Im not exactly sure what you are asking for but I hope this helps.

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The sum of two numbers is 6 The difference of the two numbers is 3 What are the two numbers.

stiv31 [10]

Answer:

4.5 and 1.5

Step-by-step explanation:

4.5+1.5=6

4.5-1.5=3(difference)

3 0

3 years ago

Read 2 more answers

Chad stop and fill the car with 11 gallons of gas he had driven 308 miles is in the previous 11 gallons of gas how many miles pe

Mrrafil [7]

308 miles per 11 gallons.

You need to find the amount of miles per 1 gallon.

dived the number of miles over gallons.

will look like:

miles
----------
gallons

it will look like for this problem

308
-------
11

308
-------- =28
11

28 miles per 1 gallon

4 0

3 years ago

Which of the following best describes the equation below?

sergiy2304 [10]

Answer:

both linear and nonlinear

5 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

Find the midpoint of the line segment with the given endpoints. R(-12, 8), S(6, 12)

umka21 [38]

Answer:

The answer is one.

Step-by-step explanation:

4 0

3 years ago