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pishuonlain [190]
3 years ago
14

5. Fatima likes to watch movies and decides to sign up for a movie subscription that will allow

Mathematics
1 answer:
pochemuha3 years ago
6 0

If you’re looking for an equation for both of these, Bob’s rentals would be 20+2m and Bella’s would just be 6m. If you are trying to figure out how many movies it would take to be the same, set up the equation 20+2m=6m and solve. Im not exactly sure what you are asking for but I hope this helps.

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I have 2 more homework questions so please I need help.....
mafiozo [28]

hope it helps you!!!!

4 0
3 years ago
If sin theta = -1/2 and lies in the third quadrant, what is the cos?
never [62]
Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.

The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.

So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

cos \: 30\degree = \sqrt{3} \div 2

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).

cos \: 210 \degree = - \sqrt{3} \div 2

5 0
3 years ago
Determine whether the data in the table can be modeled by a linear equation. Explain.
kotykmax [81]

Answer:

yes, because they're varying in a constante rate

y = -1/2x +3.5

7 0
2 years ago
The quantity a varies directly with b and c and inversely with dThe quantity d is tripledWhich of the following must be true for
EastWind [94]

Answer:

We have the next relation:

A = (b*d)/c

because we have direct variation with b and d, but inversely variation with c.

Now, if we have 3d instead of d, we have:

A' = (b*(3d))/c

now, we want A' = A. If b,c, and d are the same in both equations, we have that:

3bd/c = b*d/c

this will only be true if b or/and d are equal to 0.

If d remains unchanged, and we can play with the other two variables we have:

3b'd/c' = bd/c

3b'/c' = b/c

from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.

Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c

6 0
3 years ago
Solve the problem:
Over [174]

Answer:

Step-by-step explanation:

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4 0
2 years ago
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