Right triangle DEF is shown.

Suppose that in an alternate universe, the gambler's fallacy is true: the more a gambler loses, the more likely she is to win th

stepladder [879]

Answer and explanation:

The gambler's fallacy is the fallacy of belief that if an event such as a loss occurs more frequently in the past, it is less likely to happen in the future. We assume here that this belief is true, therefore

If she loses, her probability of winning increases =3/4

If she wins, her probability to win is normal =1/2

Given that probability of winning is 1/2

Probability of losing is 1-1/2=1/2

Probability that she wins the tournament is probability that she wins the first two games and loses the last or wins the first game, loses the second and wins the last or loses the first game and wins the last two games or probability that she wins all three games

=1/2*1/2*1/2+1/2*1/2*3/4+1/2*3/4*1/2+1/2*1/2*1/2

=25/48

Probability of winning the tournament if she loses the first game

=1/2*3/4*1/2= 3/16

Note: whenever there is "or" in probability, you add

4 0

3 years ago

I WILL MARK THE BRAINEST

Luda [366]

Answer:

blank 1: 2

blank2: 6

hope this helps

4 0

3 years ago

2x – 5x + 16 = –3(x – 6)

lapo4ka [179]

Answer:

0

Step-by-step explanation:

2x – 5x + 16 = –3(x – 6)

2x - 5x + 16 = -3x + 18

-3x + 16 = -3x + 18

0x = 1

x = 0

6 0

3 years ago

Read 2 more answers

Manny bought 12 pounds of vegetables

finlep [7]

Answer:

Manny bought 3 pounds that were not on sale

Step-by-step explanation:

If 75 % were on sale, (100% -75% = 25%) then 25% were not on sale (The total has to be 100%)

Manny bought 12 pounds of vegetables

To determine how many pounds were not on sale, we take the amount of vegetables purchased and multiply by the percent that were not on sale.

12 * 25%

Change this to decimal form

12 *.25

3

Manny bought 3 pounds that were not on sale

7 0

3 years ago

Read 2 more answers

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago