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Kamila [148]
3 years ago
12

Right triangle DEF is shown.

Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:


Step-by-step explanation:

b


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Determine whether the triangles are congruent by sss sas asa aas hl
Semmy [17]

Answer:

Congruent by SAS

Step-by-step explanation:

The three given sides of one triangle is shown to be equal to the corresponding sides of the other triangle.

This means that all threes sides of one are congruent to all corresponding sides of the other triangle.

By the Side-Side-Side Congruence Theorem, we can conclude that both triangles are congruent.

7 0
3 years ago
A drawbridge rises at a rate of 3 2/3 feet per minute. The drawbridge rises to a height of 50 feet. How long does it take the dr
k0ka [10]

Answer: Third option.

Step-by-step explanation:

You know that the drawbridge rises at a rate of 3\ \frac{2}{3} feet per minute. This means that the drawbridge rises  3\ \frac{2}{3} in a minutes.

Convert from mixed fraction to decimal number:

 3\ \frac{2}{3}\ ft=(3+0.66)\ ft=3.6\ ft

Since the drawbridge rises to a height of 50 feet, you need to apply this procedure in order to find the time the drawbridge takes to completely rise:

time=\frac{(1\ min)(50\ ft)}{3.66\ ft}=13.6\ min or 13\ \frac{7}{11}\ min

7 0
3 years ago
Read 2 more answers
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
Please solve<br>thanks ​
Korolek [52]

Answer:

1) 250°, 2) 44°

Step-by-step explanation:

1) See attached

If we add a line ⊥ to both AB and DE, we can find x as a sum of 2 internal angles of right triangles and 180°

∠D internal = 360°-312°=48°

x=180°+(90°-62°)+(90°-48°)= 180°+28°+42°= 250°

x=250°

2)

∠ADC= ∠ABC= 180°- ∠ADE= 180°- 110°= 70°

∠DBC= ∠ABC- ∠ABD= 70°-26°= 44°

∠DBC= 44°

6 0
2 years ago
Ron has a bag containing 3 green pears and 4 red pears. He randomly selects a pear then randomly selects another pear, without r
oksian1 [2.3K]
The files did not load correctly

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3 years ago
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