All categories

3 years ago

Please answer the question from the picture above:)

Mathematics

1 answer:

Darya [45]3 years ago

3 0

Answer:

It's the red figure. This is because it is rotated 180 degrees.

Step-by-step explanation:

Please mark for Brainliest!! :D Thanks!!

For more questions or more information, please comment below!

You might be interested in

(3,-7) and (9,-5)<br> What is the equation

spin [16.1K]

Answer:

y=1/3x-8

Step-by-step explanation:

let me know if not clear

6 0

3 years ago

A photograph is reduced by a scale factor of 2/3. If the original length of the photograph was 6 inches, what is the length of t

AlladinOne [14]

The answer is c, 4 inches
6 x (2/3) = 4

3 0

3 years ago

What’s the degree 2xy5

frutty [35]

Answer:

Step-by-step explanation:

The degree of the term

$2xy^5$

is the sum of the exponents of the variables, so is 1+5 = 6.

The degree of the term is 6.

6 0

3 years ago

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago

Help with this please!

slega [8]

Hello,

No, this is NOT a proportional relationship.

Have a great day/night and stay safe! :)

8 0

3 years ago

Read 2 more answers