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3 years ago

Please help...which of the following is an arithmetic sequence?

Mathematics

2 answers:

lbvjy [14]3 years ago

4 0

Answer:

0,2,4,6....

Step-by-step explanation:

Since only they have the common difference between them, they are in the arithmetic sequence

Hope it helps you

Please mark as the brainliest

Thank You

-Dominant- [34]3 years ago

3 0

Answer:

I would say its 0,2,4,6,....

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Find the x-intercept of the line whose equation is 8x + 2y = 4.<br> 04<br> 02<br> 1/2

bezimeni [28]

Answer:

1/2

Step-by-step explanation:

The x-intercept is a point on the graph that is located on any point of x but must have a y-value of 0. To find the x-intercept, we must set y in the given equation equal to 0.

8x + 2y = 4

8x + 2(0) = 4

8x = 4

x = 4/8

x = 1/2

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1 year ago

Simplify the polynomial expressions by combining like terms and then multiply the resulting binomial expressions to find their p

patriot [66]

(6x-9)(8+5x-5)=(6x-9)(5x+3)=

$=6x\cdot5x-5x\cdot9+6x\cdot3-9\cdot3=\\=30x^2-27x-27$

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2 years ago

Read 2 more answers

Find the largest prime factor of 18! + 19! + 20!

OlgaM077 [116]

Answer: Prime Factors for 18: 2, 3, and 3

Prime Factors for 19: 19

Prime Factors for 20: 2, 2, and 5

Can you mark brainlest

Step-by-step explanation:

6 0

2 years ago

Kayla is having a neighbor watch her dog while she is gone for the week she decides to take 7/8 of a pound of dog food and put i

777dan777 [17]

Answer:

1/ 8 pounds of dog food

Step-by-step explanation:

Given that:

7/8 pounds of dog food shared equally into 7 containers ;

Number of dog food in each container will be :

Total dog food / Number of containers

(7/8) ÷ 7

(7 /8) * 1/ 7

7 / 56

= 1/8 pounds of dog food

4 0

2 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago