Answer:
Each time you insert a new node, call the function to adjust the sum.
This method has to be called each time we insert new node to the tree since the sum at all the
parent nodes from the newly inserted node changes when we insert the node.
// toSumTree method will convert the tree into sum tree.
int toSumTree(struct node *node)
{
if(node == NULL)
return 0;
// Store the old value
int old_val = node->data;
// Recursively call for left and right subtrees and store the sum as new value of this node
node->data = toSumTree(node->left) + toSumTree(node->right);
// Return the sum of values of nodes in left and right subtrees and
// old_value of this node
return node->data + old_val;
}
This has the complexity of O(n).
Explanation:
D. All of the above.
<u>Reason:</u>
A. Fences can get in the way of a beautiful picture.
B: The animal's enclosure may be hard to get the perfect snap. Like a rock can be in the way of the animal. idk...lol
C. People want to see the animal as much as you do so they may block the way of a picture.
Example from Google..XD
a client-side framework is loaded on the client side, ie., the browser.
Answer:
n! = n*(n-1)*(n-2)*(n-3)* ... *2*1
Explanation:
The factorial operator is simply a mathematical expression of the product of a stated integer and all integers below that number down to 1. Consider these following examples:
4! = 4 * 3 * 2 * 1
4! = 12 * 2 * 1
4! = 24
6! = 6 * 5 * 4 * 3 * 2 * 1
6! = 30 * 4 * 3 * 2 * 1
6! = 120 * 3 * 2 * 1
6! = 360 * 2 * 1
6! = 720
So, the factorial of n would follow the same as such:
n! = n * (n-1) * (n-2) * ... * 2 * 1
Cheers.
Answer:
The main objects of a head frame, or poppet head, are to support the winding pulley firmly and to guide the cage above the surface to the discharging stage.
