There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.
Even means the graph is symmetric about the y-axis
The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)
because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).
Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
The answer is c I took that test last tear
(goh) = 2(x^1/2)-1
(goh)(9) = 2(9^1/2)-1
= 2(3)-1
= 6-1
= 5
(goh)(9) = 5
Answer:
11
Step-by-step explanation:
f(1) = 3(1) + 8 = 3 + 8 = 11
Isolate x; you must get all the constants on one side of the equation and the variables on the other side. Use subtraction/addition to do this. Reply to me once you've done that if you still need help.
