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4 years ago

Which of the binomials below is a factor of this trinomial? x² + 3x - 4

Mathematics

1 answer:

Kisachek [45]4 years ago

5 0

Answer:

(x+4) or (x-1)

Step-by-step explanation:

Do this by factoring out your equation. To do this, think about which two numbers multiply to be -4 but also add up to be 3 (the -4 came from multiplying the first value (the 1 that is attached to the $x^{2}$ ) and the last value, which is -4. The 3 came from the middle term).

The two numbers you should have gotten are 4 and -1. Therefore, (x+4) and (x-1) are both of the binomials that could be your answer

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a tour bus cost $75 plus $6 for each passenger. write and evaluate an expression to find the total cost for 25 passengers. then.

miskamm [114]

To make an expression for any amount of passengers, you need to use x for each passenger. Fill in x with the amount of passengers. Your equation is:
75 + 6x. Now using this expression, we can find the answer to all of the amounts of passengers.

75 + 6(25) = 225; 75 + 6(26) = 231; and so on. Hope that I helped! Good luck!

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3 years ago

Write 0.8 as a percentage

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4 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve the system of equations algebraically. 3x+8y=−6 x−y=9 (x,y)= (

vova2212 [387]

Step-by-step explanation:

x=y+9

substitute

3(y+9)+8y=-6

3y+27+8y= -6

13y = -6 -27

13y= -33

y = -33/13

x = -33/13 + 9

4 0

2 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago