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3 years ago

Which of the following statements about the graph is true?

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

First of all, a graph has a minimum if it is shaped like a u (a quadratic). A graph has a maximum if it is shaped like an upside-down u. The vertex of the graph is a minimum or maximum based on the graph's shape.

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Write an expression with the value of 12.It should contain four numbers and two different operations

Nady [450]

8-2+(12÷2)

Hope this helps :)

5 0

3 years ago

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What is the range of the following set? 48, 47, 54, 55, 52, 48, 46, 53, 45

umka2103 [35]

Answer:

Step-by-step explanation:

the range is the difference between the biggest and the smallest number

55-45=10

8 0

3 years ago

4(2x-3)+8(x-4)=2(2x+6) help plzzz

TEA [102]

Answer:

x = 14/3

Step-by-step explanation:

4(2x-3)+8(x-4)=2(2x+6)

Distribute

8x -12 +8x - 32 = 4x +12

Combine like terms

16x -44 = 4x+12

Subtract 4x

16x-4x -44 = 4x+12-4x

12x -44 =12

Add 44 to each side

12x-44+44 = 12+44

12x = 56

Divide each side by 12

12x/12 = 56/12

x = 14/3

8 0

3 years ago

Read 2 more answers

I don’t understand this question?

Andrej [43]

Answer:

no, because it has a constant rate of change

Step-by-step explanation:

this is because the x and y change at the same rate. non linear means that they dont change at the same rate.

5 0

3 years ago

I need help please?!):

motikmotik

Answer:

Option C: $\sqrt{\textbf{121}}$

Step-by-step explanation:

Given the side length of a square is 11 units.

Note that $\sqrt{121} = \pm 11$

Since, length cannot be negative, we can eliminate - 11.

Hence, the length of the side of the square is 11 units = $\sqrt{11^2} = \sqrt{121}$ .

Hence, the answer.

7 0

3 years ago