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3 years ago

7

Use the formula o = 7 to find the value of the missing variable 5 radians per sec, t= 9 sec = (round to the nearest thousandths)

1 answer:

ZanzabumX [31]3 years ago

8 0

Answer:

$o = 9 \times \frac{5\pi}{9} \\$

$o = 5\pi = 15.71$

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The daily cost of hiring a plumber , y , to work x hours on a repair project can be modeled using a linear function. The plumber

Paladinen [302]

Answer:

The range of the function is $80\leq y\leq 440$

Step-by-step explanation:

Consider the provided information.

The plumber charges a fixed cost of $80 plus an additional cost of $45 per hour.

Let plumber works for x hours, then the required linear function will be:

$y=45x+80$

The plumber works a maximum of 8 hours per day.

That means the minimum value of x is 0 and maximum value of x is 8.

We need to find the range of the function.

Range of the function is the set of y values.

Substitute x=0 in above function,

$y=45(0)+80$

$y=80$

Now substitute x=8 in above function.

$y=45(8)+80$

$y=360+80$

$y=440$

Hence, the range of the function is $80\leq y\leq 440$

3 0

3 years ago

Ann [662]

Answer:

9 and 41 over 51

Step-by-step explanation:

divide 41 2/3 by 4 1/4

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3 years ago

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Amber surveyed a random sample of 100 students from her middle school to learn more about what type of school lunches are prefer

Alex787 [66]

Answer:

d Hamburgers and spaghetti are preferred almost equally.

5 0

3 years ago

Find the circumference of the given circle

Soloha48 [4]

$\huge\boxed{2\pi\sqrt{41}}$

Hey! Start by finding the radius. We will assume that point $P$ is the center point of the circle, so the radius is the distance between points $P$ and $Q$ .

Let's use the distance formula, substituting in the known values:

$\begin{aligned}r&=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\&=\sqrt{(-2-3)^2+(2-(-2))^2}\end{aligned}$

Simplify:

$\begin{aligned}r&=\sqrt{(-2-3)^2+(2-(-2))^2}\\&=\sqrt{(-5)^2+4^2}\\&=\sqrt{25+16}\\&=\sqrt{41}\end{aligned}$

Now, we'll use the formula for the circumference of a circle, substituting in the known value:

$\begin{aligned}C&=2\pi r\\&=\boxed{2\pi\sqrt{41}}\\&\approx40.232\end{aligned}$

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3 years ago

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Dion ran 3.75 kilometers each day to prepare for a race. What was the number of kilometers that Dion ran during 28 days? is this

BigorU [14]

Answer:

Yes this is multiplication

Answer is: 105km

Step-by-step explanation:

multiply 3.75 by 28 to find the total number he ran

3.75•28= 105km

hope this helps chu <3

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3 years ago