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Hunter-Best [27]
3 years ago
15

Last week, a disk containing CSM Tech Publishing’s current project manuscripts crashed. Fortunately, there was a backup, but all

files that had been added or changed that day were lost. A new disk had to be purchased for overnight delivery, and the data had to be restored. Several days of work were lost. The owner of CSM Tech wants to know what can be done to prevent the loss of data and time if a disk crashes in the future. The server currently has two disks installed: one for the Windows boot and system volumes and one for manuscript files. The disk used for manuscript files is about one-third full. There’s enough money in the budget to purchase up to two new drives if needed. a. What solution do you recommend, and why?
Computers and Technology
1 answer:
liq [111]3 years ago
4 0

Answer:

They should go for cloud based model

Explanation:

Cloud based model should be sort after because with such a model there can be a restoration of contents in just a little period of time. As for the usage, payments can be done. They would have highly packed response time, turn around time and also provide information security. At a go, there is flexibility in terms of storage and information retrieval. This may be more costly though but it would be helpful for data recovery without requiring physical data transmission

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Vladimir79 [104]

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I think make a copy maybe

Explanation:

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3 years ago
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A) What is the maximum value that can be represented as an unsigned n-bit binary integer?
My name is Ann [436]

Answer:

The maximum value that are represented as unsigned n -bit binary integer is 2^n-1. The unsigned binary integer refers to the fixed point of the system that does not contain any fractional digits.

The unsigned binary integer contain module system with the power 2. The number of student table in the class is the best example of the unsigned integer. The numbers can be represented by using the binary notation and bits in the computer system.

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3 years ago
Which is the correct attribute syntax
taurus [48]

ANSWER:  GIVE ME BRAINLIEST AND ILL GIVE YOU THE ANSWER

EXPLANATION: ALL YOU NEED TO DO IS GIVE ME BRAINLIEST FOR THE ANSWER

3 0
3 years ago
I need help on this, need answer asap.
FinnZ [79.3K]

Answer:

int main() {

int _2dArray[32][32];

for (int i = 0; i < 32; i++) {

 for (int j = 0; j < 32; j++) {

  _2dArray[i][j] = j + i * 32;

 }

}

return 0;

}

Explanation:

Here is a generic C/C++ 2d array traversal and main function example. The rest you'll have to figure out based on what kind of app you're making.

Good luck!

6 0
2 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
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