Answer:
B 3.78 seconds
Step-by-step explanation:
On the graph, the line ends when it hits (0,3.78) This means that the object was in the air for 3.78 seconds before hitting the ground (0 height)
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
1/2 Kg of Cherries
Give both 2/5 and 1/10 a common denominator- 10
4/10 + 1/10 = 5/10 = 1/2
