Please answer the picture below!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
2 answers:
The formula is:
SA = s2 + 2 × s × l where s is the base side pf the piramid which is 4, and "l" is the slant hight pf the piramid the imaginary line from the tip of the piramid going perpendicular on the piramid square surface.
SA = 4^2 + 2x4x3,60
SA = 44,8
SA is the Surface Area
For detailed solving check my picture attached!
SA = s2 + 2 × s × l where s is the base side pf the piramid which is 4, and "l" is the slant hight pf the piramid the imaginary line from the tip of the piramid going perpendicular on the piramid square surface.
SA = 4^2 + 2x4x3,60
SA = 44,8
SA is the Surface Area
For detailed solving check my picture attached!
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The solution is in the attachment
Answer:
A. (0, 1) and (2, -2)
B. Slope (m) = -³/2
C. y + 2 = -³/2(x - 2)
D.
E.
Step-by-step explanation:
A. Two points on the line from the graph are: (0, 1) and (2, -2)
B. The slope can be calculated using two points, (0, 1) and (2, -2):
Slope (m) = -³/2
C. Equation in point-slope form is represented as y - b = m(x - a). Where,
(a, b) = any point on the graph.
m = slope.
Substitute (a, b) = (2, -2), and m = -³/2 into the point-slope equation, y - b = m(x - a).
Thus:
y - (-2) = -³/2(x - 2)
y + 2 = -³/2(x - 2)
D. Equation in slope-intercept form, can be written as y = mx + b.
Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.
y + 2 = -³/2(x - 2)
2(y + 2) = -3(x - 2)
2y + 4 = -3x + 6
2y = -3x + 6 - 4
2y = -3x + 2
y = -3x/2 + 2/2
E. Convert the equation in (D) to standard form: