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natima [27]
3 years ago
7

What is the range of the function y=1 +2sin(x - 11 )?

Mathematics
2 answers:
Yuri [45]3 years ago
4 0

Answer:

range of the given function in Interval notation is [-1, 3]

Step-by-step explanation:

i) given function is y = 1 + 2sin(x - 11)

ii) maximum of sin function is 1

iii) therefore maximum of given function y_{max} =  1 + (2\times 1) = 3

iv) minimum of sin function is -1

v) therefore maximum of given function y_{max} =  1 + (2\times -1) = -1

vi) therefore the range of the given function in Interval notation is [-1,3]

densk [106]3 years ago
3 0

Answer:

D. -1 to 3

Step-by-step explanation:

We have been given a function y=1+2sin(x-11 ). We are asked to find the range of the function.

We know that since oscillates between -1 and 1, that is minimum value of sin is -1 and maximum is 1.    

The range of basic sin function is -1\leq \text{sin}(x-11)\leq 1.

Now we will multiply all sides by 2.

-1\cdot 2\leq 2\cdot \text{sin}(x-11)\leq 1\cdot 2

-2\leq 2\text{sin}(x-11)\leq 2

Now we will add 1 on all sides as:

-2+1\leq 2\text{sin}(x-11)+1\leq 2+1

-1\leq 2\text{sin}(x-11)+1\leq 3

-1\leq f(x) \leq 3

Therefore, the range of the given function is [-1,3] and option D is the correct choice.

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Answer:

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Step-by-step explanation:

Answer:

y > –5x + 3

Step-by-step explanation:

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