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netineya [11]
3 years ago
15

Mr. Gengel wants to make a shelf with boards that are 1 1/3 feet long. If he has

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

At most Mr.Gengel can cut at most 13 pieces with half a foot left.

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Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two sides
cestrela7 [59]

Answer:

Choice D - 8cm and 9cm.

Step-by-step explanation:

The other sides are not greater than 13.

A: 5 + 8 = 13

B: 6 + 7 = 13

C: 7 + 2 = 9

However, <u>D is greater than 13 and is the correct answer.</u>

D: 8 + 8 = 16.

3 0
3 years ago
Can you think of any 2x2 matrices d for which cd = dc for all 2x2 matrices c? give 2 different examples of such matricesd.
Ksju [112]
For any arbitrary 2x2 matrices \mathbf C and \mathbf D, only one choice of \mathbf D exists to satisfy \mathbf{CD}=\mathbf{DC}, which is the identity matrix.

There is no other matrix that would work unless we place some more restrictions on \mathbf C. One such restriction would be to ensure that \mathbf C is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking \mathbf D=\mathbf C^{-1} we'd get equality.
6 0
3 years ago
6x-21&gt;3 and 14x+11&gt;-17
Delicious77 [7]
6x-21>3
Add 21 to both sides
6x>24
Divide 6 on both sides
X>4

14x+11>-17
Subtract 11 from both sides
14x>-28
Divide 14 on both sides
X<-2
8 0
3 years ago
The athlete drank 80% of his water bottle in the first 15 minutes of his workout. If the bottle held 16.9 ounces of water, how m
Tresset [83]

Answer:

13.52 ounces of water

Step-by-step explanation:

80% equals 8/10

So we multiply 16.9x8/10 getting 13.52 ounces

6 0
2 years ago
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
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