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jekas [21]
3 years ago
8

Find the coordinates of the reflection: B (5, 4) is reflected over the line x=1

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

The coordinates of point B' are (-3, 4) ⇒ C

Step-by-step explanation:

If the point (x, y) reflected across the line x = a, then a is the x-coordinate of the midpoint of the segment joining the point and its image

∵ The coordinates of point B are (5, 4)

∴ x = 5 and y = 4

∵ The point B is reflected over the line x = 1

→ From the rule above

∴ a = 1

∵ The rule of the midpoint is M = (\frac{x1+x2}{2} , \frac{y1+y2}{2})

→ The point B is (x1, y1) and the point B' is (x2, y2)

∵ a is the x-coordinate of the midpoint of segment BB'

∴ a = \frac{x1+x2}{2}

∵ x1 = 5 and x2 = x

→ Substitute the value of a, x1 and x2 in the rule above

∴ 1 = \frac{5+x}{2}

→ Multiply both sides by 2

∵ 2 = 5 + x

→ Subtract 5 from both sides

∴ 2 - 5 = 5 - 5 + x

∴ -3 = x

∴ The x-coordinate of B' = -3

→ y-coordinate of B' = y-coordinate of B because the reflection across

   x = a does not change the y-coordinate

∴ y-coordinate of B' = 4

∴ The coordinates of point B' are (-3, 4)

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Answer:

\boxed{y=2x^2+4x-7}

Step-by-step explanation:

Let the quadratic function be

y=ax^2+bx+c


We substitute (-4,9) into the equation to obtain;


9=a(-4)^2+b(-4)+c


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We substitute (0,-7) to obtain;


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We finally substitute (1,-1) to obtain;


-1=a(1)^2+b(1)^2+c


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We put equation (2) into equation (1) to get;


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We put a=2 into equation (5) to get;


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The reqiured quadratic function is

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