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Mariulka [41]
3 years ago
5

16. A company spends $100 per day on fixed expenses such as electricity, rent, and the like. It also spends $35 per day on each

employee working that day. Find a linear equation relating the total daily cost, C, with the number of employees working on any particular day, x.
Mathematics
2 answers:
gavmur [86]3 years ago
7 0

Answer:

C = $100+$35x

Step-by-step explanation:

Given :

A company spends $100 per day on fixed expenses such as electricity, rent, and the like.

It also spends $35 per day on each employee working that day.

To Find : a linear equation relating the total daily cost, C, with the number of employees working on any particular day, x.

Solution :

A company spend  $100 per day on fixed expenses

No. of employees working on a particular day = x

Company spend on each employee  per day = $35

It spends on x employee = $35x

Since total daily cost = C

Thus C = $100+$35x

Hence , a linear equation relating the total daily cost, C, with the number of employees working on any particular day, x. :  C = $100+$35x


Paladinen [302]3 years ago
5 0
C = Total Daily Cost
Total Daily Cost = (Salary per employee per day)×(Total no. of employees on that day) + Fixed Expenses.

C = 35x + 100
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Answer:

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f. \frac {12}{s^2 + 4} converges to s> 0.

g. -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

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Step-by-step explanation:

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b. L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3} converges to s> - 3.

d. L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25} converges to s> 0.

e. L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1} converges even s> 0.

f. L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4} converges to s> 0.

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