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ddd [48]
3 years ago
5

On the unit circle, which of the following angles has the terminal point coordinates (√2/2,-√2/2)

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

Option B

Step-by-step explanation:

A unit circle means radius of the circle = 1 unit

Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.

Center of the circle is origin (0, 0).

Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = (\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})

OP.Cosθ = 1×Cosθ = \frac{1}{\sqrt{2}}

Cosθ = \frac{1}{\sqrt{2}}

θ = \frac{\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integers

Similarly, OP×Sinθ = 1×Sinθ = -\frac{1}{\sqrt{2}}

Sinθ = -\frac{1}{\sqrt{2} }

θ = \frac{5\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integer

Common value of θ will be, θ = \frac{7\pi }{4}

Option B will be the answer.

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Answer:

m = 3a

Step-by-step explanation:

The number of pieces of candy eaten by Alex is not important.

The only thing that matters is that Marisol eats 3 times as many pieces of candy.

If a is the number eaten by Andy, then 3 times a equals the number of pieces of candy eaten by Marisol, or m=3a

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2 years ago
I need help with this fast​
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Answer:

l( longer side ) = 12cm

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D's( distance between the shorter side). ( It is also the height. I hope you got the clue…)

Anyway,

Area=9X8=72cm^2

Distance of the longer sides is

Area/the length of the longer side

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Pentagon P and pentagon Q, shown above, are congruent
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Black_prince [1.1K]

Answer:

The distance of the plane from the base of the tower is 25.5 foot.

Step-by-step explanation:

As given

Max is in a control tower at a small airport.

He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.

Now by using the trigonometric identity.

tan\theta = \frac{Perpendicular}{Base}

As shown in the figure given below

Perpendicular = CB

Base = AC = 50 feet

\theta = 27^{\circ}

Put in the identity.

tan\ 27^{\circ} = \frac{CB}{AC}

tan\ 27^{\circ} = \frac{CB}{50}

tan\ 27^{\circ} = 0.51\ (Approx)

Put in the above

0.51 = \frac{CB}{50}

CB = 0.51 × 50

CB = 25.5 foot

Therefore the distance of the plane from the base of the tower is 25.5 foot.


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Answer:

1. a. z test for means and t test for means.

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2 years ago
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