The number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles
<h3>Stoichiometry </h3>
From the question, we are to determine the number of moles of silver oxide (I) needed to produce 4 moles of silver
First, we will write the balaced chemical equation for the decomposition of silver oxide (I)
2Ag₂O(s) → 4Ag(s) + O₂(g)
This means, 2 moles of silver oxide (I) [Ag₂O] decomposes to give 4 moles of <u>silver </u>and 1 mole of oxygen gas.
From the <em>balanced chemical equation</em>, it is easy to deduce the number of moles of silver oxide (I) that would give 4 moles of silver.
Hence, the number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles
Learn more on Stoichiometry here: brainly.com/question/18834543
Answer:
A. 22.41
Explanation:
goodluck man, just typing a little bit more for the 20 words
Answer:
Explanation:
for spontaneous reaction,
ΔG is negative
K>1
E > 0
cell A:
ΔG and EO suggests that reaction is spontaneous. But K is less than 1.
Hence K is wrong
cell B:
ΔG and EO suggests that reaction is non spontaneous .But K is greater than 1.
Hence K is wrong
cell C:
E and K suggest than reaction is non spontaneous but ΔG suggest that reaction is spontaneous.
Hence ΔG is wrong
Answer:
The question involves drawing of structures and showing mechanism in which brainly text editor did not support. I made sure I created a pdf file with both the anwsers and explanations in it. The pdf can be found in the attachment below.
Explanation:
Answer:
Algo importante sobre el balance de una reacción química es la ley de la conservación de la masa que establece que la masa no se crea ni se destruye sólo se transforma de modo que en una reacción química la suma de la masa de los reactivos debe ser igual a la suma de la masa de los productos.
Por ejemplo: La fermentación de la glucosa es una reacción química balanceada que da como resultado etanol y dióxido de carbono.
C₆H₁₂O₆ → 2C₂H₆O +2CO₂
Calculando la masa de los reactivos y productos, se debe cumplir la ley de la conservación de la masa:
C₆H₁₂O₆= 6*12+12*1+6*16=180 g/mol
C₂H₆O= 2*12+6*1+16=46 g/mol
CO₂=12+2*16=44 g/mol
C₆H₁₂O₆ → 2C₂H₆O + 2CO₂
180 g/mol = 2*46 g/mol + 2*44 g/mol
180 g/mol = 92 g/mol + 88 g/mol
180 g/mol = 180 g/mol
