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nadya68 [22]
2 years ago
15

A student uses 5g of carbon to extract copper metal from its ore:

Chemistry
1 answer:
Umnica [9.8K]2 years ago
4 0

Answer:

drt4gxhknwo

Explanation:

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Write the electron configuration for a sodium cation with a charge of 1+
Dafna1 [17]

1{s}^{2} 2 {s}^{2} 2 {p}^{6}

or simply 2,8 it is isoelectronic with argon

4 0
3 years ago
Nitrogen monoxide, NO, is formed in automobile exhaust by the reaction of nitrogen and oxygen in the air: N2 (g) + O2 (g) ↔ NO (
Solnce55 [7]

Answer:

The equilibrium concentration of NO is 0.001335 M

Explanation:

Step 1: Data given

The equilibrium constant Kc is 0.0025 at 2127 °C

An equilibrium mixture contains 0.023M N2 and 0.031 M O2,

Step 2: The balanced equation

N2(g) + O2(g) ↔ 2NO(g)

Step 3:  Concentration at the equilibrium

[N2] = 0.023 M

[O2] = 0.031 M

Kc = 0.0025 = [NO]² / [N2][O2]

Kc = 0.0025 = [NO]² / (0.023)(0.031)

[NO] = 0.001335 M

The equilibrium concentration of NO is 0.001335 M

6 0
3 years ago
A cube is 4 cm on each side. What is its volume?<br><br> Answer: 64cm^3
Anit [1.1K]

Answer:

yeah

Explanation:

5 0
3 years ago
How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
2 years ago
2. How many nanoliters are in 2.87 x 10-10 gallons?
Morgarella [4.7K]

Answer:

1.09nL

Explanation:

Hello,

In this case, given that 1 gal equals 4 qt, 1 qt equals 0.9464 L and 1 L equals 1x10⁹ nL, the dimensional analysis turns out:

2.87x10^{-10}gal*\frac{4qt}{1gal} *\frac{0.9464L}{1qt}*\frac{1x10^9nL}{1L}\\  \\1.09nL

Best regards.

4 0
3 years ago
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